Derivative of 2^x

Answer

2xln⁡(2)2^{x}\ln(2)
2^x*ln(2)

Derivative of 2^x

Rule Used
Exponential Rule
Steps
  1. Recognize the exponential 2^x. For e^x the derivative equals the original function. For a^x the factor ln⁡(a)\ln(a) appears, because a^x = ex⋅ln⁡(a)e^{x\cdot \ln(a)}.
  2. Apply the rule and keep that constant factor.
  3. Final answer: 2^x*ln⁡(2)\ln(2)

d/dx 2^x = 2^x*ln(2). The expression is built from polynomials, sine, cosine, or exponentials, so the derivative exists for every real x.

Instant step-by-step solution for 2^x

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Derivative of 2^x = 2^x*ln(2) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-2-to-the-x

Derivative

2^x → 2^x*ln(2)engine: 2^x*ln(2)

Graph of the function and its derivative

f(x) f'(x)

The solid curve is f. The dashed curve is f′. Vertical gaps are asymptotes or jumps, not extra zeros.

Why the derivative has this form

2^x is not e^x. Write it as e^(x ln 2); the chain rule then multiplies by ln 2. The derivative is 2^x ln 2, written 2^x*ln(2). The ln 2 is a constant about 0.693, which is why 2^x grows more slowly than e^x.

Apply the exponential rule to 2^x. The form to remember, already simplified, is 2^x*ln(2).

The expression is built from polynomials, sine, cosine, or exponentials, so the derivative exists for every real x.

At x = 0, substitute into the simplified form 2^x*ln(2). That number is the slope of 2^x there; a secant over a small step in x lands next to it.

Worked derivative

  1. Write f(x) = 2^x.
  2. Apply the exponential rule to 2^x. The form to remember, already simplified, is 2^x*ln(2).
  3. At x = 0, substitute into the simplified form 2^x*ln(2). That number is the slope of 2^x there; a secant over a small step in x lands next to it.

Common mistakes

Answering 2^x instead of 2^x ln(2)

2^x without ln 2 treats every exponential as its own derivative. Only base e has that property.

Treating 2^x as if only the base mattered

Only e^x is its own derivative with no extra factor. A coefficient in the exponent, or a base other than e, changes the answer.

Frequently asked questions

What is the derivative of 2^x?

2^x*ln(2). 2^x is not e^x. Write it as e^(x ln 2); the chain rule then multiplies by ln 2. The derivative is 2^x ln 2, written 2^x*ln(2). The ln 2 is a constant about 0.693, which is why 2^x grows more slowly than e^x.

Which wrong answer shows up for 2^x?

2^x without ln 2 treats every exponential as its own derivative. Only base e has that property.

Where is the derivative of 2^x defined?

The expression is built from polynomials, sine, cosine, or exponentials, so the derivative exists for every real x.