Derivative of sec(x)

Answer

sin(x)cos(x)2\frac{\mathrm{sin}\left(x\right)}{\mathrm{cos}\left(x\right)^{2}}
cos(x)^(-2)*sin(x)

Derivative of sec(x)

Rule Used
Trigonometric Rule
Steps
  1. Recognize the trigonometric function sec⁡(x)\sec(x). These six derivatives are standard; a cofunction (cos, cot, csc) picks up a minus sign.
  2. Apply the standard derivative: ddxsec⁡(x)\frac{d}{dx} \sec(x) = cos⁡(x)−2\cos(x)^{-2}*sin⁡(x)\sin(x).
  3. Final answer: cos⁡(x)−2\cos(x)^{-2}*sin⁡(x)\sin(x)

d/dx sec(x) = sec(x)*tan(x). The derivative exists on the same open intervals as the function, and it blows up at the vertical asymptotes.

Instant step-by-step solution for sec(x)

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Derivative of sec(x) = cos(x)^(-2)*sin(x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sec-x

Derivative

sec(x) → sec(x)*tan(x)engine: cos(x)^(-2)*sin(x)

Graph of the function and its derivative

f(x) f'(x)

The solid curve is f. The dashed curve is f′. Vertical gaps are asymptotes or jumps, not extra zeros.

Why the derivative has this form

Secant is 1/cos(x). Differentiating the reciprocal brings −1/cos^2 times the derivative of cosine, which is −sin, so the two minuses cancel and you get sin/cos^2. That splits as (1/cos)·(sin/cos) = sec(x) tan(x). The product, not a lone tangent, is the derivative.

Apply the trigonometric derivative to sec(x). The form to remember, already simplified, is sec(x)*tan(x).

The derivative exists on the same open intervals as the function, and it blows up at the vertical asymptotes.

At x = 0.5, substitute into the simplified form sec(x)*tan(x). That number is the slope of sec(x) there; a secant over a small step in x lands next to it.

Worked derivative

  1. Write f(x) = sec(x).
  2. Apply the trigonometric derivative to sec(x). The form to remember, already simplified, is sec(x)*tan(x).
  3. At x = 0.5, substitute into the simplified form sec(x)*tan(x). That number is the slope of sec(x) there; a secant over a small step in x lands next to it.

Common mistakes

Answering tan(x)

tan(x) alone drops the secant factor. Both pieces come from sin/cos^2, and neither is optional.

Swapping sec(x) with its cofunction

Sine and cosine, tangent and cotangent, secant and cosecant are not interchangeable. The minus sign lives on the cofunction side.

Frequently asked questions

What is the derivative of sec(x)?

sec(x)*tan(x). Secant is 1/cos(x). Differentiating the reciprocal brings −1/cos^2 times the derivative of cosine, which is −sin, so the two minuses cancel and you get sin/cos^2. That splits as (1/cos)·(sin/cos) = sec(x) tan(x). The product, not a lone tangent, is the derivative.

Which wrong answer shows up for sec(x)?

tan(x) alone drops the secant factor. Both pieces come from sin/cos^2, and neither is optional.

Where is the derivative of sec(x) defined?

The derivative exists on the same open intervals as the function, and it blows up at the vertical asymptotes.