Derivative of sin(3x+1)

Answer

3⋅cos(3⋅x+1)3 \cdot \mathrm{cos}\left(3 \cdot x+1\right)
3*cos(1+3*x)

Derivative of sin(3x+1)

Rule Used
Chain Rule
Steps
  1. Identify a composite function in sin⁡(3⋅x+1)\sin(3 \cdot x+1): use the chain rule ddxf(g(x))\frac{d}{dx} f(g(x)) = f'(g(x))·g'(x). The inner derivative is required because a stretch or shift of the input changes how fast the output moves.
  2. Differentiate the outer function, then multiply by the inner derivative.
  3. Final answer: 3⋅c3 \cdot cos(1+3⋅x3 \cdot x)

The derivative of sin(3*x+1) is 3*cos(1+3*x).

Instant step-by-step solution for sin(3x+1)

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Derivative of sin(3x+1) = 3*cos(1+3*x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sin3x-minus-plus-minus-1

How to find the derivative of sin(3x+1)

To find the derivative of sin(3x+1), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.

Frequently Asked Questions

What is the derivative of sin(3x+1)?▼
The derivative of sin(3x+1) is 3*cos(1+3*x).
How do you find the derivative of sin(3x+1)?▼
Apply the standard differentiation rules — the key rule used here is the Chain Rule. The step-by-step result is 3*cos(1+3*x).
Why is the derivative of sin(3x+1) equal to 3*cos(1+3*x)?▼
Because differentiation measures how a function changes — applying the rules to sin(3x+1) yields 3*cos(1+3*x). See the full step-by-step breakdown above.