Derivative of sin(9x)*cos(9x)

Answer

−9⋅sin(9⋅x)2+9⋅cos(9⋅x)2-9 \cdot \mathrm{sin}\left(9 \cdot x\right)^{2}+9 \cdot \mathrm{cos}\left(9 \cdot x\right)^{2}
-9*sin(9*x)^2+9*cos(9*x)^2

Derivative of sin(9x)*cos(9x)

Rule Used
Product Rule
Steps
  1. Identify a product of two functions of x in sin⁡(9⋅x)\sin(9 \cdot x)*cos⁡(9⋅x)\cos(9 \cdot x): use the product rule (uv)' = u'v + uv'. Each factor is differentiated once while the other is held as-is, then the two terms are added.
  2. Differentiate each factor and combine.
  3. Final answer: -9⋅s9 \cdot sin(9⋅x9 \cdot x)^2+9⋅c9 \cdot cos(9⋅x9 \cdot x)^2

The derivative of sin(9*x)*cos(9*x) is -9*sin(9*x)^2+9*cos(9*x)^2.

Instant step-by-step solution for sin(9x)*cos(9x)

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Derivative of sin(9x)*cos(9x) = -9*sin(9*x)^2+9*cos(9*x)^2 Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sin9xcos9x

How to find the derivative of sin(9x)*cos(9x)

To find the derivative of sin(9x)*cos(9x), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.

Frequently Asked Questions

What is the derivative of sin(9x)*cos(9x)?▼
The derivative of sin(9x)*cos(9x) is -9*sin(9*x)^2+9*cos(9*x)^2.
How do you find the derivative of sin(9x)*cos(9x)?▼
Apply the standard differentiation rules — the key rule used here is the Product Rule. The step-by-step result is -9*sin(9*x)^2+9*cos(9*x)^2.
Why is the derivative of sin(9x)*cos(9x) equal to -9*sin(9*x)^2+9*cos(9*x)^2?▼
Because differentiation measures how a function changes — applying the rules to sin(9x)*cos(9x) yields -9*sin(9*x)^2+9*cos(9*x)^2. See the full step-by-step breakdown above.