Derivative of e^x is e^x

Answer

exe^{x}
e^x

Derivative of e^x

Rule Used
Exponential Rule
Steps
  1. Recognize the exponential e^x. For e^x the derivative equals the original function. For a^x the factor ln⁡(a)\ln(a) appears, because a^x = ex⋅ln⁡(a)e^{x\cdot \ln(a)}.
  2. Apply the rule and keep that constant factor.
  3. Final answer: e^x

The derivative of e^x is e^x: the function is its own derivative.

Instant step-by-step solution for e^x

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Derivative

e^x → e^xengine: e^x

Graph of the function and its derivative

f(x) f'(x)

The solid curve is f. The dashed curve is f′. Vertical gaps are asymptotes or jumps, not extra zeros.

Why the derivative has this form

For a general base a, the derivative of a^x is a^x ln(a). The number e is the unique base for which ln(a) = 1, so the extra factor disappears. Equivalently, e is chosen so that the slope of a^x at x = 0 is exactly 1. Every other exponential is a constant multiple of that slope, which is why e^x is the natural one to differentiate.

From the definition, (e^(x+h) - e^x)/h = e^x (e^h - 1)/h. The limit (e^h - 1)/h -> 1 is the defining property of e, so the difference quotient tends to e^x. The limit is not an approximation: it is what the number e was selected to satisfy.

A function equal to its own derivative grows at a rate proportional to its size. At x = 0 the value and the slope are both 1; at x = ln(2) both are 2; at x = 5 both are about 148.4. This is the reason e^x models unconstrained growth, and why adding a constant multiple C·e^x still solves y' = y.

From the difference quotient to the fixed point

  1. Write the difference quotient (e^(x+h) - e^x)/h.
  2. Factor out e^x using e^(x+h) = e^x·e^h, giving e^x (e^h - 1)/h.
  3. Use the defining limit of e: (e^h - 1)/h -> 1 as h approaches 0.
  4. Multiply: e^x·1 = e^x. The derivative equals the original function.
  5. Contrast with a general base: d/dx a^x = a^x ln(a). Only a = e removes the factor.
  6. Check at x = 0: e^0 = 1 and the slope is 1, so the tangent line is y = x + 1.
  7. Check the chain rule on e^(2x): the inner derivative 2 comes down, giving 2e^(2x).

Worked example

Value and slope of e^x at x = ln(2), and the tangent at x = 0

  1. At x = ln(2), e^x = 2. Because the derivative is the same function, the slope there is also 2.
  2. The tangent line at that point is y - 2 = 2(x - ln(2)).
  3. At x = 0 the value is 1 and the slope is 1, so the tangent line is y - 1 = x, or y = x + 1.
  4. A secant from 0 to 0.001 gives (e^0.001 - 1)/0.001, about 1.0005, confirming the unit slope at the origin.

Answer: 2

Common mistakes

Applying the power rule and answering x·e^(x-1)

The power rule applies when the exponent is a constant and x is the base. In e^x the base is constant and x is the exponent, so the rule does not apply. x·e^(x-1) is not the derivative of any elementary exponential.

Forgetting ln(a) for other bases

The derivative of 2^x is 2^x ln(2), about 0.693·2^x. Dropping that factor and writing e^x also changes the base, not just the coefficient.

Dropping the chain-rule factor on e^(kx)

The derivative of e^(2x) is 2e^(2x) and of e^(-x) is -e^(-x). The exponent is a function of x, so its derivative must come down as a factor.

Frequently asked questions

What is the derivative of e^x?

The derivative of e^x is e^x. It is the only function (up to a constant multiple) equal to its own derivative.

Why does e^x differentiate to itself?

The difference quotient is e^x(e^h - 1)/h, and e is defined so that (e^h - 1)/h -> 1. The quotient therefore tends to e^x.

What is the derivative of 2^x?

It is 2^x ln(2). For a general base a the derivative of a^x is a^x ln(a); e is the base where ln(a) = 1.

What is the derivative of e^(2x)?

Use the chain rule: 2e^(2x). The derivative of the inner 2x comes down as a factor of 2.