Derivative of sign(x)

Answer

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0

Derivative of sign(x)

Rule Used
Power Rule
Steps
  1. Identify the expression as a power function and apply the power rule. A rational exponent is allowed: ddxx\frac{d}{dx} x^(p/q) = (p/q)·xp/q−1x^{p/q - 1}.
  2. Final answer: 0

d/dx sign(x) = 0. The derivative is 0 for x < 0 and for x > 0. It does not exist at x = 0, where sign(x) jumps.

Instant step-by-step solution for sign(x)

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Derivative of sign(x) = 0 Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sign-x

Derivative

sign(x) → 0engine: 0

Graph of the function and its derivative

f(x) f'(x)

The solid curve is f. The dashed curve is f′. Vertical gaps are asymptotes or jumps, not extra zeros.

Why the derivative has this form

sign(x) is −1 on the negatives, undefined or zero at the origin depending on convention, and +1 on the positives. On each open half-line the function is constant, so the slope is 0. The engine reports 0, and that answer is right only away from zero. At x = 0 the function jumps, and a jump has no derivative. Do not read the printed 0 as a derivative at the origin.

Apply the definition as a limit to sign(x). The form to remember, already simplified, is 0.

The derivative is 0 for x < 0 and for x > 0. It does not exist at x = 0, where sign(x) jumps.

At x = 2, substitute into the simplified form 0. That number is the slope of sign(x) there; a secant over a small step in x lands next to it.

Worked derivative

  1. Write f(x) = sign(x).
  2. Apply the definition as a limit to sign(x). The form to remember, already simplified, is 0.
  3. At x = 2, substitute into the simplified form 0. That number is the slope of sign(x) there; a secant over a small step in x lands next to it.

Common mistakes

Answering 1

Answering 1 confuses the value of the function on the right with its slope. The pieces are horizontal, so the slope is 0, not 1.

Claiming sign(x) has a derivative at the bad point

Corners and jumps are exactly where a formula that works on each piece fails. State the pieces and then state the exception.

Frequently asked questions

What is the derivative of sign(x)?

0. sign(x) is −1 on the negatives, undefined or zero at the origin depending on convention, and +1 on the positives. On each open half-line the function is constant, so the slope is 0. The engine reports 0, and that answer is right only away from zero. At x = 0 the function jumps, and a jump has no derivative. Do not read the printed 0 as a derivative at the origin.

Which wrong answer shows up for sign(x)?

Answering 1 confuses the value of the function on the right with its slope. The pieces are horizontal, so the slope is 0, not 1.

Where is the derivative of sign(x) defined?

The derivative is 0 for x < 0 and for x > 0. It does not exist at x = 0, where sign(x) jumps.