Derivative of sin(2x+1)

Answer

2⋅cos(2⋅x+1)2 \cdot \mathrm{cos}\left(2 \cdot x+1\right)
2*cos(1+2*x)

Derivative of sin(2x+1)

Rule Used
Chain Rule
Steps
  1. Identify a composite function in sin⁡(2⋅x+1)\sin(2 \cdot x+1): use the chain rule ddxf(g(x))\frac{d}{dx} f(g(x)) = f'(g(x))·g'(x). The inner derivative is required because a stretch or shift of the input changes how fast the output moves.
  2. Differentiate the outer function, then multiply by the inner derivative.
  3. Final answer: 2⋅c2 \cdot cos(1+2⋅x2 \cdot x)

The derivative of sin(2*x+1) is 2*cos(1+2*x).

Instant step-by-step solution for sin(2x+1)

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Derivative of sin(2x+1) = 2*cos(1+2*x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sin2x-minus-plus-minus-1

How to find the derivative of sin(2x+1)

To find the derivative of sin(2x+1), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.

Frequently Asked Questions

What is the derivative of sin(2x+1)?▼
The derivative of sin(2x+1) is 2*cos(1+2*x).
How do you find the derivative of sin(2x+1)?▼
Apply the standard differentiation rules — the key rule used here is the Chain Rule. The step-by-step result is 2*cos(1+2*x).
Why is the derivative of sin(2x+1) equal to 2*cos(1+2*x)?▼
Because differentiation measures how a function changes — applying the rules to sin(2x+1) yields 2*cos(1+2*x). See the full step-by-step breakdown above.