Derivative of sin(3x)+cos(2x)

Answer

−2⋅sin(2⋅x)+3⋅cos(3⋅x)-2 \cdot \mathrm{sin}\left(2 \cdot x\right)+3 \cdot \mathrm{cos}\left(3 \cdot x\right)
-2*sin(2*x)+3*cos(3*x)

Derivative of sin(3x)+cos(2x)

Rule Used
Sum Rule
Steps
  1. Differentiate sin⁡(3⋅x)\sin(3 \cdot x)+cos⁡(2⋅x)\cos(2 \cdot x) term by term. The sum rule says the derivative of a sum is the sum of the derivatives, and the derivative of a constant term is 0, so that term disappears.
  2. Final answer: -2⋅s2 \cdot sin(2⋅x2 \cdot x)+3⋅c3 \cdot cos(3⋅x3 \cdot x)

The derivative of sin(3*x)+cos(2*x) is -2*sin(2*x)+3*cos(3*x).

Instant step-by-step solution for sin(3x)+cos(2x)

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Derivative of sin(3x)+cos(2x) = -2*sin(2*x)+3*cos(3*x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sin3x-minus-plus-minus-cos2x

How to find the derivative of sin(3x)+cos(2x)

To find the derivative of sin(3x)+cos(2x), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.

Frequently Asked Questions

What is the derivative of sin(3x)+cos(2x)?▼
The derivative of sin(3x)+cos(2x) is -2*sin(2*x)+3*cos(3*x).
How do you find the derivative of sin(3x)+cos(2x)?▼
Apply the standard differentiation rules — the key rule used here is the Sum Rule. The step-by-step result is -2*sin(2*x)+3*cos(3*x).
Why is the derivative of sin(3x)+cos(2x) equal to -2*sin(2*x)+3*cos(3*x)?▼
Because differentiation measures how a function changes — applying the rules to sin(3x)+cos(2x) yields -2*sin(2*x)+3*cos(3*x). See the full step-by-step breakdown above.