Derivative of sin(6x)+cos(3x)

Answer

−3⋅sin(3⋅x)+6⋅cos(6⋅x)-3 \cdot \mathrm{sin}\left(3 \cdot x\right)+6 \cdot \mathrm{cos}\left(6 \cdot x\right)
-3*sin(3*x)+6*cos(6*x)

Derivative of sin(6x)+cos(3x)

Rule Used
Sum Rule
Steps
  1. Differentiate sin⁡(6⋅x)\sin(6 \cdot x)+cos⁡(3⋅x)\cos(3 \cdot x) term by term. The sum rule says the derivative of a sum is the sum of the derivatives, and the derivative of a constant term is 0, so that term disappears.
  2. Final answer: -3⋅s3 \cdot sin(3⋅x3 \cdot x)+6⋅c6 \cdot cos(6⋅x6 \cdot x)

The derivative of sin(6*x)+cos(3*x) is -3*sin(3*x)+6*cos(6*x).

Instant step-by-step solution for sin(6x)+cos(3x)

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Derivative of sin(6x)+cos(3x) = -3*sin(3*x)+6*cos(6*x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-sin6x-minus-plus-minus-cos3x

How to find the derivative of sin(6x)+cos(3x)

To find the derivative of sin(6x)+cos(3x), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.

Frequently Asked Questions

What is the derivative of sin(6x)+cos(3x)?▼
The derivative of sin(6x)+cos(3x) is -3*sin(3*x)+6*cos(6*x).
How do you find the derivative of sin(6x)+cos(3x)?▼
Apply the standard differentiation rules — the key rule used here is the Sum Rule. The step-by-step result is -3*sin(3*x)+6*cos(6*x).
Why is the derivative of sin(6x)+cos(3x) equal to -3*sin(3*x)+6*cos(6*x)?▼
Because differentiation measures how a function changes — applying the rules to sin(6x)+cos(3x) yields -3*sin(3*x)+6*cos(6*x). See the full step-by-step breakdown above.