Derivative of tan(5x)*sec(5x)
Answer
5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x)
Derivative of tan(5x)*sec(5x)
- Rule Used
- Product Rule
- Steps
- Identify a product of two functions of x in *: use the product rule (uv)' = u'v + uv'. Each factor is differentiated once while the other is held as-is, then the two terms are added.
- Differentiate each factor and combine.
- Final answer: os()^(-1)*+os()^(-2)**
The derivative of tan(5*x)*sec(5*x) is 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x).
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Derivative of tan(5x)*sec(5x) = 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x) Solve step-by-step for free: https://derivativecalculatorai.com/derivative-of-tan5xsec5x
How to find the derivative of tan(5x)*sec(5x)
To find the derivative of tan(5x)*sec(5x), we use standard differentiation rules. Our AI-powered calculator breaks down the steps and explains the logic.
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Frequently Asked Questions
What is the derivative of tan(5x)*sec(5x)?▼
The derivative of tan(5x)*sec(5x) is 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x).
How do you find the derivative of tan(5x)*sec(5x)?▼
Apply the standard differentiation rules — the key rule used here is the Product Rule. The step-by-step result is 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x).
Why is the derivative of tan(5x)*sec(5x) equal to 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x)?▼
Because differentiation measures how a function changes — applying the rules to tan(5x)*sec(5x) yields 5*cos(5*x)^(-1)*sec(5*x)^2+5*cos(5*x)^(-2)*sin(5*x)*tan(5*x). See the full step-by-step breakdown above.