Derivada de ln(x^2-1)

Answer

2⋅xx2−1\frac{2 \cdot x}{x^{2}-1}
2*(-1+x^2)^(-1)*x

Derivative of ln(x^2-1)

Rule Used
Chain Rule
Steps
  1. Identify a composite function in log⁡(x2−1)\log(x^2-1): use the chain rule ddxf(g(x))\frac{d}{dx} f(g(x)) = f'(g(x))·g'(x). The inner derivative is required because a stretch or shift of the input changes how fast the output moves.
  2. Differentiate the outer function, then multiply by the inner derivative.
  3. Final answer: 2*(-1+x2x^2)^(-1)*x

La derivada de ln(x^2-1) es 2*(-1+x^2)^(-1)*x.

Solución paso a paso instantánea para ln(x^2-1)

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Derivative of ln(x^2-1) = 2*(-1+x^2)^(-1)*x Solve step-by-step for free: https://derivativecalculatorai.com/es/derivative-of-lnx-minus-to-minus-the-minus-2-minus-1

Cómo encontrar la derivada de ln(x^2-1)

Para encontrar la derivada de ln(x^2-1), usamos reglas de diferenciación estándar. Nuestra calculadora con IA desglosa los pasos y explica la lógica.

Frequently Asked Questions

What is the derivative of ln(x^2-1)?▼
The derivative of ln(x^2-1) is 2*(-1+x^2)^(-1)*x.
How do you find the derivative of ln(x^2-1)?▼
Apply the standard differentiation rules — the key rule used here is the Chain Rule. The step-by-step result is 2*(-1+x^2)^(-1)*x.
Why is the derivative of ln(x^2-1) equal to 2*(-1+x^2)^(-1)*x?▼
Because differentiation measures how a function changes — applying the rules to ln(x^2-1) yields 2*(-1+x^2)^(-1)*x. See the full step-by-step breakdown above.